2.25x^2-12x-48=0

Solution for 2.25x^2-12x-48=0 equation:

2.25x^2-12x-48=0

a = 2.25; b = -12; c = -48;
Δ = b2-4ac
Δ = -122-4·2.25·(-48)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-24}{2*2.25}=\frac{-12}{4.5}
=-2+3/4.5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+24}{2*2.25}=\frac{36}{4.5}
=8
$